Solve (-4.5)+(-4/3)+(-3/4)+45+(-7/3)+0.25

$$( - 4.5 ) + ( - \frac { 4 } { 3 } ) + ( - \frac { 3 } { 4 } ) + 45 + ( - \frac { 7 } { 3 } ) + 0.25$$

Evaluate

$$\frac{109}{3}\approx 36.333333333$$

Solution Steps

Convert decimal number -4.5 to fraction -\frac{45}{10}. Reduce the fraction -\frac{45}{10} to lowest terms by extracting and canceling out 5.

$$-\frac{9}{2}-\frac{4}{3}-\frac{3}{4}+45-\frac{7}{3}+0.25$$

Least common multiple of 2 and 3 is 6. Convert -\frac{9}{2} and \frac{4}{3} to fractions with denominator 6.

$$-\frac{27}{6}-\frac{8}{6}-\frac{3}{4}+45-\frac{7}{3}+0.25$$

Since -\frac{27}{6} and \frac{8}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-27-8}{6}-\frac{3}{4}+45-\frac{7}{3}+0.25$$

Subtract 8 from -27 to get -35.

$$-\frac{35}{6}-\frac{3}{4}+45-\frac{7}{3}+0.25$$

Least common multiple of 6 and 4 is 12. Convert -\frac{35}{6} and \frac{3}{4} to fractions with denominator 12.

$$-\frac{70}{12}-\frac{9}{12}+45-\frac{7}{3}+0.25$$

Since -\frac{70}{12} and \frac{9}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-70-9}{12}+45-\frac{7}{3}+0.25$$

Subtract 9 from -70 to get -79.

$$-\frac{79}{12}+45-\frac{7}{3}+0.25$$

Convert 45 to fraction \frac{540}{12}.

$$-\frac{79}{12}+\frac{540}{12}-\frac{7}{3}+0.25$$

Since -\frac{79}{12} and \frac{540}{12} have the same denominator, add them by adding their numerators.

$$\frac{-79+540}{12}-\frac{7}{3}+0.25$$

Add -79 and 540 to get 461.

$$\frac{461}{12}-\frac{7}{3}+0.25$$

Least common multiple of 12 and 3 is 12. Convert \frac{461}{12} and \frac{7}{3} to fractions with denominator 12.

$$\frac{461}{12}-\frac{28}{12}+0.25$$

Since \frac{461}{12} and \frac{28}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{461-28}{12}+0.25$$

Subtract 28 from 461 to get 433.

$$\frac{433}{12}+0.25$$

Convert decimal number 0.25 to fraction \frac{25}{100}. Reduce the fraction \frac{25}{100} to lowest terms by extracting and canceling out 25.

$$\frac{433}{12}+\frac{1}{4}$$

Least common multiple of 12 and 4 is 12. Convert \frac{433}{12} and \frac{1}{4} to fractions with denominator 12.

$$\frac{433}{12}+\frac{3}{12}$$

Since \frac{433}{12} and \frac{3}{12} have the same denominator, add them by adding their numerators.

$$\frac{433+3}{12}$$

Add 433 and 3 to get 436.

$$\frac{436}{12}$$

Reduce the fraction \frac{436}{12} to lowest terms by extracting and canceling out 4.

$$\frac{109}{3}$$

Factor

$$\frac{109}{3} = 36\frac{1}{3} = 36.333333333333336$$