Solve (-4c-5)+(-9c-9)

$$( - 4 c - 5 ) + ( - 9 c - 9 )$$

Evaluate

$$-13c-14$$

Solution Steps

Combine -4c and -9c to get -13c.

$$-13c-5-9$$

Subtract 9 from -5 to get -14.

$$-13c-14$$

Differentiate w.r.t. c

$$-13$$

Steps Using Derivative Rule for Sum

Combine -4c and -9c to get -13c.

$$\frac{\mathrm{d}}{\mathrm{d}c}(-13c-5-9)$$

Subtract 9 from -5 to get -14.

$$\frac{\mathrm{d}}{\mathrm{d}c}(-13c-14)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-13c^{1-1}$$

Subtract 1 from 1.

$$-13c^{0}$$

For any term t except 0, t^{0}=1.

$$-13$$