Solve (-4b^3)(1/6a^2)(-9b^4)

$$( - 4 b ^ { 3 } ) ( \frac { 1 } { 6 } a ^ { 2 } ) ( - 9 b ^ { 4 } )$$

Evaluate

$$6a^{2}b^{7}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 3 and 4 to get 7.

$$-4b^{7}\times \frac{1}{6}a^{2}\left(-9\right)$$

Multiply -4 and \frac{1}{6} to get -\frac{2}{3}.

$$-\frac{2}{3}b^{7}a^{2}\left(-9\right)$$

Multiply -\frac{2}{3} and -9 to get 6.

$$6b^{7}a^{2}$$

Differentiate w.r.t. a

$$12ab^{7}$$