Solve (-4)^3div(-2)^5+2div(-10)^0=

$$( - 4 ) ^ { 3 } \div ( - 2 ) ^ { 5 } + 2 \div ( - 10 ) ^ { 0 } =$$

Evaluate

$$4$$

Solution Steps

Calculate -4 to the power of 3 and get -64.

$$\frac{-64}{\left(-2\right)^{5}}+\frac{2}{\left(-10\right)^{0}}$$

Calculate -2 to the power of 5 and get -32.

$$\frac{-64}{-32}+\frac{2}{\left(-10\right)^{0}}$$

Divide -64 by -32 to get 2.

$$2+\frac{2}{\left(-10\right)^{0}}$$

Calculate -10 to the power of 0 and get 1.

$$2+\frac{2}{1}$$

Anything divided by one gives itself.

$$2+2$$

Add 2 and 2 to get 4.

$$4$$

Factor

$$2^{2}$$