Solve (-4)^2-4(-1)(-k+2)=0

$$( - 4 ) ^ { 2 } - 4 ( - 1 ) ( - k + 2 ) = 0$$

Solve for k

$$k=6$$

Steps for Solving Linear Equation

Calculate -4 to the power of 2 and get 16.

$$16-4\left(-1\right)\left(-k+2\right)=0$$

Multiply 4 and -1 to get -4.

$$16-\left(-4\left(-k+2\right)\right)=0$$

The opposite of -4\left(-k+2\right) is 4\left(-k+2\right).

$$16+4\left(-k+2\right)=0$$

Use the distributive property to multiply 4 by -k+2.

$$16+4\left(-k\right)+8=0$$

Add 16 and 8 to get 24.

$$24+4\left(-k\right)=0$$

Subtract 24 from both sides. Anything subtracted from zero gives its negation.

$$4\left(-k\right)=-24$$

Divide both sides by 4.

$$-k=\frac{-24}{4}$$

Divide -24 by 4 to get -6.

$$-k=-6$$

Multiply both sides by -1.

$$k=6$$