Solve (-4)^2+(pi-3)^0-2^3-|-5|

$$( - 4 ) ^ { 2 } + ( \pi - 3 ) ^ { 0 } - 2 ^ { 3 } - | - 5 |$$

Evaluate

$$4$$

Solution Steps

Calculate -4 to the power of 2 and get 16.

$$16+\left(\pi -3\right)^{0}-2^{3}-|-5|$$

Calculate \pi -3 to the power of 0 and get 1.

$$16+1-2^{3}-|-5|$$

Add 16 and 1 to get 17.

$$17-2^{3}-|-5|$$

Calculate 2 to the power of 3 and get 8.

$$17-8-|-5|$$

Subtract 8 from 17 to get 9.

$$9-|-5|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -5 is 5.

$$9-5$$

Subtract 5 from 9 to get 4.

$$4$$

Factor

$$2^{2}$$