Solve (-4)^0+2^3-(-3)^2+(-2)^2

$$( - 4 ) ^ { 0 } + 2 ^ { 3 } - ( - 3 ) ^ { 2 } + ( - 2 ) ^ { 2 }$$

Evaluate

$$4$$

Solution Steps

Calculate -4 to the power of 0 and get 1.

$$1+2^{3}-\left(-3\right)^{2}+\left(-2\right)^{2}$$

Calculate 2 to the power of 3 and get 8.

$$1+8-\left(-3\right)^{2}+\left(-2\right)^{2}$$

Add 1 and 8 to get 9.

$$9-\left(-3\right)^{2}+\left(-2\right)^{2}$$

Calculate -3 to the power of 2 and get 9.

$$9-9+\left(-2\right)^{2}$$

Subtract 9 from 9 to get 0.

$$0+\left(-2\right)^{2}$$

Calculate -2 to the power of 2 and get 4.

$$0+4$$

Add 0 and 4 to get 4.

$$4$$

Factor

$$2^{2}$$