Solve (-4sqrt{2})^2=8x

$$( - 4 \sqrt { 2 } ) ^ { 2 } = 8 x$$

Solve for x

$$x=4$$

Steps for Solving Linear Equation

Expand \left(-4\sqrt{2}\right)^{2}.

$$\left(-4\right)^{2}\left(\sqrt{2}\right)^{2}=8x$$

Calculate -4 to the power of 2 and get 16.

$$16\left(\sqrt{2}\right)^{2}=8x$$

The square of \sqrt{2} is 2.

$$16\times 2=8x$$

Multiply 16 and 2 to get 32.

$$32=8x$$

Swap sides so that all variable terms are on the left hand side.

$$8x=32$$

Divide both sides by 8.

$$x=\frac{32}{8}$$

Divide 32 by 8 to get 4.

$$x=4$$