Solve (-4+a^2)^2

$$( - 4 + a ^ { 2 } ) ^ { 2 }$$

Evaluate

$$\left(a^{2}-4\right)^{2}$$

Solution Steps

Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(-4+a^{2}\right)^{2}.

$$16-8a^{2}+\left(a^{2}\right)^{2}$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$16-8a^{2}+a^{4}$$

Expand

$$a^{4}-8a^{2}+16$$

Solution Steps

Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(-4+a^{2}\right)^{2}.

$$16-8a^{2}+\left(a^{2}\right)^{2}$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$16-8a^{2}+a^{4}$$