Solve (-3x^2y)(4xy^2)(-2x^3y^4)

$$( - 3 x ^ { 2 } y ) ( 4 x y ^ { 2 } ) ( - 2 x ^ { 3 } y ^ { 4 } )$$

Evaluate

$$24x^{6}y^{7}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$-3x^{3}y\times 4y^{2}\left(-2\right)x^{3}y^{4}$$

To multiply powers of the same base, add their exponents. Add 3 and 3 to get 6.

$$-3x^{6}y\times 4y^{2}\left(-2\right)y^{4}$$

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$-3x^{6}y^{3}\times 4\left(-2\right)y^{4}$$

To multiply powers of the same base, add their exponents. Add 3 and 4 to get 7.

$$-3x^{6}y^{7}\times 4\left(-2\right)$$

Multiply -3 and 4 to get -12.

$$-12x^{6}y^{7}\left(-2\right)$$

Multiply -12 and -2 to get 24.

$$24x^{6}y^{7}$$

Differentiate w.r.t. x

$$144x^{5}y^{7}$$