Solve (-3j-2k)(-3j+2k)quad18

$$( - 3 j - 2 k ) ( - 3 j + 2 k ) \quad 18$$

Evaluate

$$162j^{2}-72k^{2}$$

Solution Steps

Apply the distributive property by multiplying each term of -3j-2k by each term of -3j+2k.

$$\left(9j^{2}-6jk+6kj-4k^{2}\right)\times 18$$

Combine -6jk and 6kj to get 0.

$$\left(9j^{2}-4k^{2}\right)\times 18$$

Use the distributive property to multiply 9j^{2}-4k^{2} by 18.

$$162j^{2}-72k^{2}$$

Expand

$$162j^{2}-72k^{2}$$

Solution Steps

Apply the distributive property by multiplying each term of -3j-2k by each term of -3j+2k.

$$\left(9j^{2}-6jk+6kj-4k^{2}\right)\times 18$$

Combine -6jk and 6kj to get 0.

$$\left(9j^{2}-4k^{2}\right)\times 18$$

Use the distributive property to multiply 9j^{2}-4k^{2} by 18.

$$162j^{2}-72k^{2}$$