Solve (-3b^{4}-4b^{3}-5b^2+b-14)+(-6b^4+9b^3+b^2+16b+6)

$$( - 3 b ^ { 4 } - 4 b ^ { 3 } - 5 b ^ { 2 } + b - 14 ) + ( - 6 b ^ { 4 } + 9 b ^ { 3 } + b ^ { 2 } + 16 b + 6 )$$

Evaluate

$$-9b^{4}+5b^{3}-4b^{2}+17b-8$$

Solution Steps

Combine -3b^{4} and -6b^{4} to get -9b^{4}.

$$-9b^{4}-4b^{3}-5b^{2}+b-14+9b^{3}+b^{2}+16b+6$$

Combine -4b^{3} and 9b^{3} to get 5b^{3}.

$$-9b^{4}+5b^{3}-5b^{2}+b-14+b^{2}+16b+6$$

Combine -5b^{2} and b^{2} to get -4b^{2}.

$$-9b^{4}+5b^{3}-4b^{2}+b-14+16b+6$$

Combine b and 16b to get 17b.

$$-9b^{4}+5b^{3}-4b^{2}+17b-14+6$$

Add -14 and 6 to get -8.

$$-9b^{4}+5b^{3}-4b^{2}+17b-8$$

Differentiate w.r.t. b

$$17-8b+15b^{2}-36b^{3}$$