Solve (-3ab)(-a^2c)*6abc^2

$$( - 3 a b ) ( - a ^ { 2 } c ) \cdot 6 a b c ^ { 2 }$$

Evaluate

$$18b^{2}c^{3}a^{4}$$

Solution Steps

Multiply a and a to get a^{2}.

$$-3a^{2}b\left(-a^{2}\right)c\times 6bc^{2}$$

Multiply b and b to get b^{2}.

$$-3a^{2}b^{2}\left(-a^{2}\right)c\times 6c^{2}$$

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$-3a^{2}b^{2}\left(-a^{2}\right)c^{3}\times 6$$

Multiply -3 and 6 to get -18.

$$-18a^{2}b^{2}\left(-a^{2}\right)c^{3}$$

Multiply -18 and -1 to get 18.

$$18a^{2}b^{2}a^{2}c^{3}$$

To multiply powers of the same base, add their exponents. Add 2 and 2 to get 4.

$$18a^{4}b^{2}c^{3}$$

Differentiate w.r.t. b

$$36bc^{3}a^{4}$$