Solve (-3a^2+2+5ab)+(-3ab+a^2)+(2a^2-2-2ab)

$$( - 3 a ^ { 2 } + 2 + 5 a b ) + ( - 3 a b + a ^ { 2 } ) + ( 2 a ^ { 2 } - 2 - 2 a b )$$

Evaluate

$$0$$

Solution Steps

Combine 5ab and -3ab to get 2ab.

$$-3a^{2}+2+2ab+a^{2}+2a^{2}-2-2ab$$

Combine -3a^{2} and a^{2} to get -2a^{2}.

$$-2a^{2}+2+2ab+2a^{2}-2-2ab$$

Combine -2a^{2} and 2a^{2} to get 0.

$$2+2ab-2-2ab$$

Subtract 2 from 2 to get 0.

$$2ab-2ab$$

Combine 2ab and -2ab to get 0.

$$0$$

Factor

$$0$$