Solve (-3-2)^2-(-4)^2-[(12div2)-(-3)*4)]}?

$$( - 3 - 2 ) ^ { 2 } - ( - 4 ) ^ { 2 } - [ ( 12 \div 2 ) - ( - 3 ) \times 4 ) ] \} ?$$

Evaluate

$$-9$$

Solution Steps

Subtract 2 from -3 to get -5.

$$\left(-5\right)^{2}-\left(-4\right)^{2}-\left(\frac{12}{2}-\left(-3\times 4\right)\right)$$

Calculate -5 to the power of 2 and get 25.

$$25-\left(-4\right)^{2}-\left(\frac{12}{2}-\left(-3\times 4\right)\right)$$

Calculate -4 to the power of 2 and get 16.

$$25-16-\left(\frac{12}{2}-\left(-3\times 4\right)\right)$$

Subtract 16 from 25 to get 9.

$$9-\left(\frac{12}{2}-\left(-3\times 4\right)\right)$$

Divide 12 by 2 to get 6.

$$9-\left(6-\left(-3\times 4\right)\right)$$

Multiply -3 and 4 to get -12.

$$9-\left(6-\left(-12\right)\right)$$

The opposite of -12 is 12.

$$9-\left(6+12\right)$$

Add 6 and 12 to get 18.

$$9-18$$

Subtract 18 from 9 to get -9.

$$-9$$

Factor

$$-9$$