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2^{n-1}=\frac{-1536}{-3}
Divide both sides by -3.
2^{n-1}=512
Divide -1536 by -3 to get 512.
\log(2^{n-1})=\log(512)
Take the logarithm of both sides of the equation.
\left(n-1\right)\log(2)=\log(512)
The logarithm of a number raised to a power is the power times the logarithm of the number.
n-1=\frac{\log(512)}{\log(2)}
Divide both sides by \log(2).
n-1=\log_{2}\left(512\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
n=9-\left(-1\right)
Add 1 to both sides of the equation.