Solve (-3)(2/4+3/8)+(2/4+3/6)

$$( - 3 ) ( \frac { 2 } { 4 } + \frac { 3 } { 8 } ) + ( \frac { 2 } { 4 } + \frac { 3 } { 6 } )$$

Evaluate

$$-\frac{13}{8}=-1.625$$

Solution Steps

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$-3\left(\frac{1}{2}+\frac{3}{8}\right)+\frac{2}{4}+\frac{3}{6}$$

Least common multiple of 2 and 8 is 8. Convert \frac{1}{2} and \frac{3}{8} to fractions with denominator 8.

$$-3\left(\frac{4}{8}+\frac{3}{8}\right)+\frac{2}{4}+\frac{3}{6}$$

Since \frac{4}{8} and \frac{3}{8} have the same denominator, add them by adding their numerators.

$$-3\times \frac{4+3}{8}+\frac{2}{4}+\frac{3}{6}$$

Add 4 and 3 to get 7.

$$-3\times \frac{7}{8}+\frac{2}{4}+\frac{3}{6}$$

Express -3\times \frac{7}{8} as a single fraction.

$$\frac{-3\times 7}{8}+\frac{2}{4}+\frac{3}{6}$$

Multiply -3 and 7 to get -21.

$$\frac{-21}{8}+\frac{2}{4}+\frac{3}{6}$$

Fraction \frac{-21}{8} can be rewritten as -\frac{21}{8} by extracting the negative sign.

$$-\frac{21}{8}+\frac{2}{4}+\frac{3}{6}$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$-\frac{21}{8}+\frac{1}{2}+\frac{3}{6}$$

Least common multiple of 8 and 2 is 8. Convert -\frac{21}{8} and \frac{1}{2} to fractions with denominator 8.

$$-\frac{21}{8}+\frac{4}{8}+\frac{3}{6}$$

Since -\frac{21}{8} and \frac{4}{8} have the same denominator, add them by adding their numerators.

$$\frac{-21+4}{8}+\frac{3}{6}$$

Add -21 and 4 to get -17.

$$-\frac{17}{8}+\frac{3}{6}$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$-\frac{17}{8}+\frac{1}{2}$$

Least common multiple of 8 and 2 is 8. Convert -\frac{17}{8} and \frac{1}{2} to fractions with denominator 8.

$$-\frac{17}{8}+\frac{4}{8}$$

Since -\frac{17}{8} and \frac{4}{8} have the same denominator, add them by adding their numerators.

$$\frac{-17+4}{8}$$

Add -17 and 4 to get -13.

$$-\frac{13}{8}$$

Factor

$$-\frac{13}{8} = -1\frac{5}{8} = -1.625$$