Solve (-3)^5:(-3)^3-2^3*2=

$$( - 3 ) ^ { 5 } : ( - 3 ) ^ { 3 } - 2 ^ { 3 } \cdot 2 =$$

Evaluate

$$-7$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 3 from 5 to get 2.

$$\left(-3\right)^{2}-2^{3}\times 2$$

To multiply powers of the same base, add their exponents. Add 3 and 1 to get 4.

$$\left(-3\right)^{2}-2^{4}$$

Calculate -3 to the power of 2 and get 9.

$$9-2^{4}$$

Calculate 2 to the power of 4 and get 16.

$$9-16$$

Subtract 16 from 9 to get -7.

$$-7$$

Factor

$$-7$$