Solve (-3)^4+7(-3)^3+16(-3)^2+28(-5)+48

$$( - 3 ) ^ { 4 } + 7 ( - 3 ) ^ { 3 } + 16 ( - 3 ) ^ { 2 } + 28 ( - 5 ) + 48$$

Evaluate

$$-56$$

Solution Steps

Calculate -3 to the power of 4 and get 81.

$$81+7\left(-3\right)^{3}+16\left(-3\right)^{2}+28\left(-5\right)+48$$

Calculate -3 to the power of 3 and get -27.

$$81+7\left(-27\right)+16\left(-3\right)^{2}+28\left(-5\right)+48$$

Multiply 7 and -27 to get -189.

$$81-189+16\left(-3\right)^{2}+28\left(-5\right)+48$$

Subtract 189 from 81 to get -108.

$$-108+16\left(-3\right)^{2}+28\left(-5\right)+48$$

Calculate -3 to the power of 2 and get 9.

$$-108+16\times 9+28\left(-5\right)+48$$

Multiply 16 and 9 to get 144.

$$-108+144+28\left(-5\right)+48$$

Add -108 and 144 to get 36.

$$36+28\left(-5\right)+48$$

Multiply 28 and -5 to get -140.

$$36-140+48$$

Subtract 140 from 36 to get -104.

$$-104+48$$

Add -104 and 48 to get -56.

$$-56$$

Factor

$$-56$$