Solve (-3)^4+2*(-3)^3-9*(-3)^2-2(-3)+9=

$$( - 3 ) ^ { 4 } + 2 \cdot ( - 3 ) ^ { 3 } - 9 \cdot ( - 3 ) ^ { 2 } - 2 ( - 3 ) + 9 =$$

Evaluate

$$-39$$

Solution Steps

Calculate -3 to the power of 4 and get 81.

$$81+2\left(-3\right)^{3}-9\left(-3\right)^{2}-2\left(-3\right)+9$$

Calculate -3 to the power of 3 and get -27.

$$81+2\left(-27\right)-9\left(-3\right)^{2}-2\left(-3\right)+9$$

Multiply 2 and -27 to get -54.

$$81-54-9\left(-3\right)^{2}-2\left(-3\right)+9$$

Subtract 54 from 81 to get 27.

$$27-9\left(-3\right)^{2}-2\left(-3\right)+9$$

Calculate -3 to the power of 2 and get 9.

$$27-9\times 9-2\left(-3\right)+9$$

Multiply 9 and 9 to get 81.

$$27-81-2\left(-3\right)+9$$

Subtract 81 from 27 to get -54.

$$-54-2\left(-3\right)+9$$

Multiply 2 and -3 to get -6.

$$-54-\left(-6\right)+9$$

The opposite of -6 is 6.

$$-54+6+9$$

Add -54 and 6 to get -48.

$$-48+9$$

Add -48 and 9 to get -39.

$$-39$$

Factor

$$-39$$