Solve (-3)^3+(-1)^18-(-7)^0+3^4=

$$( - 3 ) ^ { 3 } + ( - 1 ) ^ { 18 } - ( - 7 ) ^ { 0 } + 3 ^ { 4 } =$$

Evaluate

$$54$$

Solution Steps

Calculate -3 to the power of 3 and get -27.

$$-27+\left(-1\right)^{18}-\left(-7\right)^{0}+3^{4}$$

Calculate -1 to the power of 18 and get 1.

$$-27+1-\left(-7\right)^{0}+3^{4}$$

Add -27 and 1 to get -26.

$$-26-\left(-7\right)^{0}+3^{4}$$

Calculate -7 to the power of 0 and get 1.

$$-26-1+3^{4}$$

Subtract 1 from -26 to get -27.

$$-27+3^{4}$$

Calculate 3 to the power of 4 and get 81.

$$-27+81$$

Add -27 and 81 to get 54.

$$54$$

Factor

$$2\times 3^{3}$$