Solve (-3)^2-2^3+3^0+(-2)^3

$$( - 3 ) ^ { 2 } - 2 ^ { 3 } + 3 ^ { 0 } + ( - 2 ) ^ { 3 }$$

Evaluate

$$-6$$

Solution Steps

Calculate -3 to the power of 2 and get 9.

$$9-2^{3}+3^{0}+\left(-2\right)^{3}$$

Calculate 2 to the power of 3 and get 8.

$$9-8+3^{0}+\left(-2\right)^{3}$$

Subtract 8 from 9 to get 1.

$$1+3^{0}+\left(-2\right)^{3}$$

Calculate 3 to the power of 0 and get 1.

$$1+1+\left(-2\right)^{3}$$

Add 1 and 1 to get 2.

$$2+\left(-2\right)^{3}$$

Calculate -2 to the power of 3 and get -8.

$$2-8$$

Subtract 8 from 2 to get -6.

$$-6$$

Factor

$$-6$$