Solve (-3)^2*(-2^2)-(-4^2):(-2)^3=

$$( - 3 ) ^ { 2 } \cdot ( - 2 ^ { 2 } ) - ( - 4 ^ { 2 } ) : ( - 2 ) ^ { 3 } =$$

Evaluate

$$-38$$

Solution Steps

Calculate -3 to the power of 2 and get 9.

$$9\left(-2^{2}\right)-\frac{-4^{2}}{\left(-2\right)^{3}}$$

Calculate 2 to the power of 2 and get 4.

$$9\left(-4\right)-\frac{-4^{2}}{\left(-2\right)^{3}}$$

Multiply 9 and -4 to get -36.

$$-36-\frac{-4^{2}}{\left(-2\right)^{3}}$$

Calculate 4 to the power of 2 and get 16.

$$-36-\frac{-16}{\left(-2\right)^{3}}$$

Calculate -2 to the power of 3 and get -8.

$$-36-\frac{-16}{-8}$$

Divide -16 by -8 to get 2.

$$-36-2$$

Subtract 2 from -36 to get -38.

$$-38$$

Factor

$$-38$$