Solve (-3)^2+2^4*(-1/2)^3

$$( - 3 ) ^ { 2 } + 2 ^ { 4 } \cdot ( - \frac { 1 } { 2 } ) ^ { 3 }$$

Evaluate

$$7$$

Solution Steps

Calculate -3 to the power of 2 and get 9.

$$9+2^{4}\left(-\frac{1}{2}\right)^{3}$$

Calculate 2 to the power of 4 and get 16.

$$9+16\left(-\frac{1}{2}\right)^{3}$$

Calculate -\frac{1}{2} to the power of 3 and get -\frac{1}{8}.

$$9+16\left(-\frac{1}{8}\right)$$

Express 16\left(-\frac{1}{8}\right) as a single fraction.

$$9+\frac{16\left(-1\right)}{8}$$

Multiply 16 and -1 to get -16.

$$9+\frac{-16}{8}$$

Divide -16 by 8 to get -2.

$$9-2$$

Subtract 2 from 9 to get 7.

$$7$$

Factor

$$7$$