Solve (-3*4+8)^2-sqrt[3]{-5^2-2-3}^0

$$( - 3 \times 4 + 8 ) ^ { 2 } - \sqrt[ 3 ] { - 5 ^ { 2 } - 2 - 3 } ^ { 0 }$$

Evaluate

$$15$$

Solution Steps

Multiply -3 and 4 to get -12.

$$\left(-12+8\right)^{2}-\left(\sqrt[3]{-5^{2}-2-3}\right)^{0}$$

Add -12 and 8 to get -4.

$$\left(-4\right)^{2}-\left(\sqrt[3]{-5^{2}-2-3}\right)^{0}$$

Calculate -4 to the power of 2 and get 16.

$$16-\left(\sqrt[3]{-5^{2}-2-3}\right)^{0}$$

Calculate 5 to the power of 2 and get 25.

$$16-\left(\sqrt[3]{-25-2-3}\right)^{0}$$

Subtract 2 from -25 to get -27.

$$16-\left(\sqrt[3]{-27-3}\right)^{0}$$

Subtract 3 from -27 to get -30.

$$16-\left(\sqrt[3]{-30}\right)^{0}$$

Calculate \sqrt[3]{-30} to the power of 0 and get 1.

$$16-1$$

Subtract 1 from 16 to get 15.

$$15$$

Factor

$$3\times 5$$