Solve (-31/2-3/4)*(-2/5)=

$$( - 3 \frac { 1 } { 2 } - \frac { 3 } { 4 } ) \times ( - \frac { 2 } { 5 } ) =$$

Evaluate

$$\frac{17}{10}=1.7$$

Solution Steps

Multiply 3 and 2 to get 6.

$$\left(-\frac{6+1}{2}-\frac{3}{4}\right)\left(-\frac{2}{5}\right)$$

Add 6 and 1 to get 7.

$$\left(-\frac{7}{2}-\frac{3}{4}\right)\left(-\frac{2}{5}\right)$$

Least common multiple of 2 and 4 is 4. Convert -\frac{7}{2} and \frac{3}{4} to fractions with denominator 4.

$$\left(-\frac{14}{4}-\frac{3}{4}\right)\left(-\frac{2}{5}\right)$$

Since -\frac{14}{4} and \frac{3}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-14-3}{4}\left(-\frac{2}{5}\right)$$

Subtract 3 from -14 to get -17.

$$-\frac{17}{4}\left(-\frac{2}{5}\right)$$

Multiply -\frac{17}{4} times -\frac{2}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-17\left(-2\right)}{4\times 5}$$

Do the multiplications in the fraction \frac{-17\left(-2\right)}{4\times 5}.

$$\frac{34}{20}$$

Reduce the fraction \frac{34}{20} to lowest terms by extracting and canceling out 2.

$$\frac{17}{10}$$

Factor

$$\frac{17}{2 \cdot 5} = 1\frac{7}{10} = 1.7$$