Solve (-3+8.5)^0+(3.1-4)^1+(2-3)-4.sqrt{25}=

$$( - 3 + 8.5 ) ^ { 0 } + ( 3.1 - 4 ) ^ { 1 } + ( 2 - 3 ) - 4 . \sqrt { 25 } =$$

Evaluate

$$-4.9$$

Solution Steps

Add -3 and 8.5 to get 5.5.

$$5.5^{0}+\left(3.1-4\right)^{1}+2-3-4$$

Calculate 5.5 to the power of 0 and get 1.

$$1+\left(3.1-4\right)^{1}+2-3-4$$

Subtract 4 from 3.1 to get -0.9.

$$1+\left(-0.9\right)^{1}+2-3-4$$

Calculate -0.9 to the power of 1 and get -0.9.

$$1-0.9+2-3-4$$

Subtract 0.9 from 1 to get 0.1.

$$0.1+2-3-4$$

Add 0.1 and 2 to get 2.1.

$$2.1-3-4$$

Subtract 3 from 2.1 to get -0.9.

$$-0.9-4$$

Subtract 4 from -0.9 to get -4.9.

$$-4.9$$

Factor

$$-4.9$$