Solve (-3+1/2)+(-3-1/2)*2-3*1/4

$$( - 3 + \frac { 1 } { 2 } ) + ( - 3 - \frac { 1 } { 2 } ) \times 2 - 3 \times \frac { 1 } { 4 }$$

Evaluate

$$-\frac{41}{4}=-10.25$$

Solution Steps

Convert -3 to fraction -\frac{6}{2}.

$$-\frac{6}{2}+\frac{1}{2}+\left(-3-\frac{1}{2}\right)\times 2-3\times \frac{1}{4}$$

Since -\frac{6}{2} and \frac{1}{2} have the same denominator, add them by adding their numerators.

$$\frac{-6+1}{2}+\left(-3-\frac{1}{2}\right)\times 2-3\times \frac{1}{4}$$

Add -6 and 1 to get -5.

$$-\frac{5}{2}+\left(-3-\frac{1}{2}\right)\times 2-3\times \frac{1}{4}$$

Convert -3 to fraction -\frac{6}{2}.

$$-\frac{5}{2}+\left(-\frac{6}{2}-\frac{1}{2}\right)\times 2-3\times \frac{1}{4}$$

Since -\frac{6}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{5}{2}+\frac{-6-1}{2}\times 2-3\times \frac{1}{4}$$

Subtract 1 from -6 to get -7.

$$-\frac{5}{2}-\frac{7}{2}\times 2-3\times \frac{1}{4}$$

Cancel out 2 and 2.

$$-\frac{5}{2}-7-3\times \frac{1}{4}$$

Convert 7 to fraction \frac{14}{2}.

$$-\frac{5}{2}-\frac{14}{2}-3\times \frac{1}{4}$$

Since -\frac{5}{2} and \frac{14}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-5-14}{2}-3\times \frac{1}{4}$$

Subtract 14 from -5 to get -19.

$$-\frac{19}{2}-3\times \frac{1}{4}$$

Multiply 3 and \frac{1}{4} to get \frac{3}{4}.

$$-\frac{19}{2}-\frac{3}{4}$$

Least common multiple of 2 and 4 is 4. Convert -\frac{19}{2} and \frac{3}{4} to fractions with denominator 4.

$$-\frac{38}{4}-\frac{3}{4}$$

Since -\frac{38}{4} and \frac{3}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-38-3}{4}$$

Subtract 3 from -38 to get -41.

$$-\frac{41}{4}$$

Factor

$$-\frac{41}{4} = -10\frac{1}{4} = -10.25$$