Solve (-27p)*2p+qdiv4s

$$( - 27 p ) \cdot 2 p + q \div 4 s$$

Evaluate

$$\frac{qs}{4}-54p^{2}$$

Short Solution Steps

Multiply p and p to get p^{2}.

$$-27p^{2}\times 2+\frac{q}{4}s$$

Multiply -27 and 2 to get -54.

$$-54p^{2}+\frac{q}{4}s$$

Express \frac{q}{4}s as a single fraction.

$$-54p^{2}+\frac{qs}{4}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply -54p^{2} times \frac{4}{4}.

$$\frac{4\left(-54\right)p^{2}}{4}+\frac{qs}{4}$$

Since \frac{4\left(-54\right)p^{2}}{4} and \frac{qs}{4} have the same denominator, add them by adding their numerators.

$$\frac{4\left(-54\right)p^{2}+qs}{4}$$

Do the multiplications in 4\left(-54\right)p^{2}+qs.

$$\frac{-216p^{2}+qs}{4}$$

Factor

$$\frac{qs-216p^{2}}{4}$$

Solution Steps

Factor out \frac{1}{4}.

$$\frac{-216pp+qs}{4}$$