Solve (-2575)+41/4+(-425)+(+203/4)=

$$( - 2575 ) + 4 \frac { 1 } { 4 } + ( - 425 ) + ( + 20 \frac { 3 } { 4 } ) =$$

Evaluate

$$-2975$$

Solution Steps

Multiply 4 and 4 to get 16.

$$-2575+\frac{16+1}{4}-425+\frac{20\times 4+3}{4}$$

Add 16 and 1 to get 17.

$$-2575+\frac{17}{4}-425+\frac{20\times 4+3}{4}$$

Convert -2575 to fraction -\frac{10300}{4}.

$$-\frac{10300}{4}+\frac{17}{4}-425+\frac{20\times 4+3}{4}$$

Since -\frac{10300}{4} and \frac{17}{4} have the same denominator, add them by adding their numerators.

$$\frac{-10300+17}{4}-425+\frac{20\times 4+3}{4}$$

Add -10300 and 17 to get -10283.

$$-\frac{10283}{4}-425+\frac{20\times 4+3}{4}$$

Convert 425 to fraction \frac{1700}{4}.

$$-\frac{10283}{4}-\frac{1700}{4}+\frac{20\times 4+3}{4}$$

Since -\frac{10283}{4} and \frac{1700}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-10283-1700}{4}+\frac{20\times 4+3}{4}$$

Subtract 1700 from -10283 to get -11983.

$$-\frac{11983}{4}+\frac{20\times 4+3}{4}$$

Multiply 20 and 4 to get 80.

$$-\frac{11983}{4}+\frac{80+3}{4}$$

Add 80 and 3 to get 83.

$$-\frac{11983}{4}+\frac{83}{4}$$

Since -\frac{11983}{4} and \frac{83}{4} have the same denominator, add them by adding their numerators.

$$\frac{-11983+83}{4}$$

Add -11983 and 83 to get -11900.

$$\frac{-11900}{4}$$

Divide -11900 by 4 to get -2975.

$$-2975$$

Factor

$$-2975$$