Solve (-2,7)+11/3+1,6+(-45/6)

$$( - 2,7 ) + 1 \frac { 1 } { 3 } + 1,6 + ( - 4 \frac { 5 } { 6 } )$$

Evaluate

$$-4,6$$

Solution Steps

Multiply 1 and 3 to get 3.

$$-2,7+\frac{3+1}{3}+1,6-\frac{4\times 6+5}{6}$$

Add 3 and 1 to get 4.

$$-2,7+\frac{4}{3}+1,6-\frac{4\times 6+5}{6}$$

Convert decimal number -2,7 to fraction -\frac{27}{10}.

$$-\frac{27}{10}+\frac{4}{3}+1,6-\frac{4\times 6+5}{6}$$

Least common multiple of 10 and 3 is 30. Convert -\frac{27}{10} and \frac{4}{3} to fractions with denominator 30.

$$-\frac{81}{30}+\frac{40}{30}+1,6-\frac{4\times 6+5}{6}$$

Since -\frac{81}{30} and \frac{40}{30} have the same denominator, add them by adding their numerators.

$$\frac{-81+40}{30}+1,6-\frac{4\times 6+5}{6}$$

Add -81 and 40 to get -41.

$$-\frac{41}{30}+1,6-\frac{4\times 6+5}{6}$$

Convert decimal number 1,6 to fraction \frac{16}{10}. Reduce the fraction \frac{16}{10} to lowest terms by extracting and canceling out 2.

$$-\frac{41}{30}+\frac{8}{5}-\frac{4\times 6+5}{6}$$

Least common multiple of 30 and 5 is 30. Convert -\frac{41}{30} and \frac{8}{5} to fractions with denominator 30.

$$-\frac{41}{30}+\frac{48}{30}-\frac{4\times 6+5}{6}$$

Since -\frac{41}{30} and \frac{48}{30} have the same denominator, add them by adding their numerators.

$$\frac{-41+48}{30}-\frac{4\times 6+5}{6}$$

Add -41 and 48 to get 7.

$$\frac{7}{30}-\frac{4\times 6+5}{6}$$

Multiply 4 and 6 to get 24.

$$\frac{7}{30}-\frac{24+5}{6}$$

Add 24 and 5 to get 29.

$$\frac{7}{30}-\frac{29}{6}$$

Least common multiple of 30 and 6 is 30. Convert \frac{7}{30} and \frac{29}{6} to fractions with denominator 30.

$$\frac{7}{30}-\frac{145}{30}$$

Since \frac{7}{30} and \frac{145}{30} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7-145}{30}$$

Subtract 145 from 7 to get -138.

$$\frac{-138}{30}$$

Reduce the fraction \frac{-138}{30} to lowest terms by extracting and canceling out 6.

$$-\frac{23}{5}$$

Factor

$$-4,6$$