( - 2,4 ) \quad 2 x + 3 y = 6
Solve for x
x=\frac{5\left(y-2\right)}{8}
Solve for y
y=\frac{8x}{5}+2
Graph
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-4,8x+3y=6
Multiply -2,4 and 2 to get -4,8.
-4,8x=6-3y
Subtract 3y from both sides.
\frac{-4,8x}{-4,8}=\frac{6-3y}{-4,8}
Divide both sides of the equation by -4,8, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{6-3y}{-4,8}
Dividing by -4,8 undoes the multiplication by -4,8.
x=\frac{5y}{8}-\frac{5}{4}
Divide 6-3y by -4,8 by multiplying 6-3y by the reciprocal of -4,8.
-4,8x+3y=6
Multiply -2,4 and 2 to get -4,8.
3y=6+4,8x
Add 4,8x to both sides.
3y=\frac{24x}{5}+6
The equation is in standard form.
\frac{3y}{3}=\frac{\frac{24x}{5}+6}{3}
Divide both sides by 3.
y=\frac{\frac{24x}{5}+6}{3}
Dividing by 3 undoes the multiplication by 3.
y=\frac{8x}{5}+2
Divide 6+\frac{24x}{5} by 3.
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