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-10t^{2}-7t+5+4t-3
Combine -2t^{2} and -8t^{2} to get -10t^{2}.
-10t^{2}-3t+5-3
Combine -7t and 4t to get -3t.
-10t^{2}-3t+2
Subtract 3 from 5 to get 2.
factor(-10t^{2}-7t+5+4t-3)
Combine -2t^{2} and -8t^{2} to get -10t^{2}.
factor(-10t^{2}-3t+5-3)
Combine -7t and 4t to get -3t.
factor(-10t^{2}-3t+2)
Subtract 3 from 5 to get 2.
-10t^{2}-3t+2=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
t=\frac{-\left(-3\right)±\sqrt{\left(-3\right)^{2}-4\left(-10\right)\times 2}}{2\left(-10\right)}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
t=\frac{-\left(-3\right)±\sqrt{9-4\left(-10\right)\times 2}}{2\left(-10\right)}
Square -3.
t=\frac{-\left(-3\right)±\sqrt{9+40\times 2}}{2\left(-10\right)}
Multiply -4 times -10.
t=\frac{-\left(-3\right)±\sqrt{9+80}}{2\left(-10\right)}
Multiply 40 times 2.
t=\frac{-\left(-3\right)±\sqrt{89}}{2\left(-10\right)}
Add 9 to 80.
t=\frac{3±\sqrt{89}}{2\left(-10\right)}
The opposite of -3 is 3.
t=\frac{3±\sqrt{89}}{-20}
Multiply 2 times -10.
t=\frac{\sqrt{89}+3}{-20}
Now solve the equation t=\frac{3±\sqrt{89}}{-20} when ± is plus. Add 3 to \sqrt{89}.
t=\frac{-\sqrt{89}-3}{20}
Divide 3+\sqrt{89} by -20.
t=\frac{3-\sqrt{89}}{-20}
Now solve the equation t=\frac{3±\sqrt{89}}{-20} when ± is minus. Subtract \sqrt{89} from 3.
t=\frac{\sqrt{89}-3}{20}
Divide 3-\sqrt{89} by -20.
-10t^{2}-3t+2=-10\left(t-\frac{-\sqrt{89}-3}{20}\right)\left(t-\frac{\sqrt{89}-3}{20}\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute \frac{-3-\sqrt{89}}{20} for x_{1} and \frac{-3+\sqrt{89}}{20} for x_{2}.