Solve (-2m)^2=4p-8

$$( - 2 m ) ^ { 2 } = 4 p - 8$$

Solve for p

$$p=m^{2}+2$$

Steps for Solving Linear Equation

Expand \left(-2m\right)^{2}.

$$\left(-2\right)^{2}m^{2}=4p-8$$

Calculate -2 to the power of 2 and get 4.

$$4m^{2}=4p-8$$

Swap sides so that all variable terms are on the left hand side.

$$4p-8=4m^{2}$$

Add 8 to both sides.

$$4p=4m^{2}+8$$

Divide both sides by 4.

$$\frac{4p}{4}=\frac{4m^{2}+8}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$p=\frac{4m^{2}+8}{4}$$

Divide 4m^{2}+8 by 4.

$$p=m^{2}+2$$

Solve for m

$$m=\sqrt{p-2}$$

$$m=-\sqrt{p-2}\text{, }p\geq 2$$