Solve (-2ab^2)(-1/3a^3b)(-4ax)

$$( - 2 a b ^ { 2 } ) ( - \frac { 1 } { 3 } a ^ { 3 } b ) ( - 4 a x )$$

Evaluate

$$-\frac{8xb^{3}a^{5}}{3}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$-2a^{4}b^{2}\left(-\frac{1}{3}\right)b\left(-4\right)ax$$

To multiply powers of the same base, add their exponents. Add 4 and 1 to get 5.

$$-2a^{5}b^{2}\left(-\frac{1}{3}\right)b\left(-4\right)x$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$-2a^{5}b^{3}\left(-\frac{1}{3}\right)\left(-4\right)x$$

Multiply -2 and -\frac{1}{3} to get \frac{2}{3}.

$$\frac{2}{3}a^{5}b^{3}\left(-4\right)x$$

Multiply \frac{2}{3} and -4 to get -\frac{8}{3}.

$$-\frac{8}{3}a^{5}b^{3}x$$

Differentiate w.r.t. x

$$-\frac{8b^{3}a^{5}}{3}$$