Solve (-2a^2bc)*(9ab^3c)*(abc

$$( - 2 a ^ { 2 } b c ) \cdot ( 9 a b ^ { 3 } c ) \cdot ( a b c$$

Evaluate

$$-18c^{3}a^{4}b^{5}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$-2a^{3}bc\times 9b^{3}cabc$$

To multiply powers of the same base, add their exponents. Add 3 and 1 to get 4.

$$-2a^{4}bc\times 9b^{3}cbc$$

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$-2a^{4}b^{4}c\times 9cbc$$

To multiply powers of the same base, add their exponents. Add 4 and 1 to get 5.

$$-2a^{4}b^{5}c\times 9cc$$

Multiply c and c to get c^{2}.

$$-2a^{4}b^{5}c^{2}\times 9c$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$-2a^{4}b^{5}c^{3}\times 9$$

Multiply -2 and 9 to get -18.

$$-18a^{4}b^{5}c^{3}$$

Differentiate w.r.t. a

$$-72b^{5}\left(ac\right)^{3}$$