Solve (-2a^2b)*(-a^2b^2)=

$$( - 2 a ^ { 2 } b ) \cdot ( - a ^ { 2 } b ^ { 2 } ) =$$

Evaluate

$$2b^{3}a^{4}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$-2a^{2}b^{3}\left(-a^{2}\right)$$

Multiply -2 and -1 to get 2.

$$2a^{2}b^{3}a^{2}$$

To multiply powers of the same base, add their exponents. Add 2 and 2 to get 4.

$$2a^{4}b^{3}$$

Differentiate w.r.t. a

$$8\left(ab\right)^{3}$$