Evaluate
\text{Indeterminate}
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4+4\sqrt{-7}+\left(\sqrt{-7}\right)^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(-2-\sqrt{-7}\right)^{2}.
4+4\sqrt{-7}-7
Calculate \sqrt{-7} to the power of 2 and get -7.
-3+4\sqrt{-7}
Subtract 7 from 4 to get -3.
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