Solve (-2)^9*(-2)^5+2^7*(-2)^7

$$( - 2 ) ^ { 9 } \cdot ( - 2 ) ^ { 5 } + 2 ^ { 7 } \cdot ( - 2 ) ^ { 7 }$$

Evaluate

$$0$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 9 and 5 to get 14.

$$\left(-2\right)^{14}+2^{7}\left(-2\right)^{7}$$

Calculate -2 to the power of 14 and get 16384.

$$16384+2^{7}\left(-2\right)^{7}$$

Calculate 2 to the power of 7 and get 128.

$$16384+128\left(-2\right)^{7}$$

Calculate -2 to the power of 7 and get -128.

$$16384+128\left(-128\right)$$

Multiply 128 and -128 to get -16384.

$$16384-16384$$

Subtract 16384 from 16384 to get 0.

$$0$$

Factor

$$0$$