Solve (-2)^4+(0,5)^2:(+0,1)^3-(-5)^3

$$( - 2 ) ^ { 4 } + ( 0,5 ) ^ { 2 } : ( + 0,1 ) ^ { 3 } - ( - 5 ) ^ { 3 }$$

Evaluate

$$391$$

Solution Steps

Calculate -2 to the power of 4 and get 16.

$$16+\frac{0,5^{2}}{0,1^{3}}-\left(-5\right)^{3}$$

Calculate 0,5 to the power of 2 and get 0,25.

$$16+\frac{0,25}{0,1^{3}}-\left(-5\right)^{3}$$

Calculate 0,1 to the power of 3 and get 0,001.

$$16+\frac{0,25}{0,001}-\left(-5\right)^{3}$$

Expand \frac{0,25}{0,001} by multiplying both numerator and the denominator by 1000. Anything divided by one gives itself.

$$16+250-\left(-5\right)^{3}$$

Add 16 and 250 to get 266.

$$266-\left(-5\right)^{3}$$

Calculate -5 to the power of 3 and get -125.

$$266-\left(-125\right)$$

The opposite of -125 is 125.

$$266+125$$

Add 266 and 125 to get 391.

$$391$$

Factor

$$17\times 23$$