Solve (-2)^{4}+(-2)^3+(-2)^2+(-2)^1+(-2)^0

$$( - 2 ) ^ { 4 } + ( - 2 ) ^ { 3 } + ( - 2 ) ^ { 2 } + ( - 2 ) ^ { 1 } + ( - 2 ) ^ { 0 }$$

Evaluate

$$11$$

Solution Steps

Calculate -2 to the power of 4 and get 16.

$$16+\left(-2\right)^{3}+\left(-2\right)^{2}+\left(-2\right)^{1}+\left(-2\right)^{0}$$

Calculate -2 to the power of 3 and get -8.

$$16-8+\left(-2\right)^{2}+\left(-2\right)^{1}+\left(-2\right)^{0}$$

Subtract 8 from 16 to get 8.

$$8+\left(-2\right)^{2}+\left(-2\right)^{1}+\left(-2\right)^{0}$$

Calculate -2 to the power of 2 and get 4.

$$8+4+\left(-2\right)^{1}+\left(-2\right)^{0}$$

Add 8 and 4 to get 12.

$$12+\left(-2\right)^{1}+\left(-2\right)^{0}$$

Calculate -2 to the power of 1 and get -2.

$$12-2+\left(-2\right)^{0}$$

Subtract 2 from 12 to get 10.

$$10+\left(-2\right)^{0}$$

Calculate -2 to the power of 0 and get 1.

$$10+1$$

Add 10 and 1 to get 11.

$$11$$

Factor

$$11$$