Solve (-2)^3div4/7-27*(-2/3)^2

$$( - 2 ) ^ { 3 } \div \frac { 4 } { 7 } - 27 \times ( - \frac { 2 } { 3 } ) ^ { 2 }$$

Evaluate

$$-26$$

Solution Steps

Calculate -2 to the power of 3 and get -8.

$$\frac{-8}{\frac{4}{7}}-27\left(-\frac{2}{3}\right)^{2}$$

Divide -8 by \frac{4}{7} by multiplying -8 by the reciprocal of \frac{4}{7}.

$$-8\times \frac{7}{4}-27\left(-\frac{2}{3}\right)^{2}$$

Express -8\times \frac{7}{4} as a single fraction.

$$\frac{-8\times 7}{4}-27\left(-\frac{2}{3}\right)^{2}$$

Multiply -8 and 7 to get -56.

$$\frac{-56}{4}-27\left(-\frac{2}{3}\right)^{2}$$

Divide -56 by 4 to get -14.

$$-14-27\left(-\frac{2}{3}\right)^{2}$$

Calculate -\frac{2}{3} to the power of 2 and get \frac{4}{9}.

$$-14-27\times \frac{4}{9}$$

Express 27\times \frac{4}{9} as a single fraction.

$$-14-\frac{27\times 4}{9}$$

Multiply 27 and 4 to get 108.

$$-14-\frac{108}{9}$$

Divide 108 by 9 to get 12.

$$-14-12$$

Subtract 12 from -14 to get -26.

$$-26$$

Factor

$$-26$$