Solve (-2)^3*(-2)^2*(-2)^0*(-2)=

$$( - 2 ) ^ { 3 } \cdot ( - 2 ) ^ { 2 } \cdot ( - 2 ) ^ { 0 } \cdot ( - 2 ) =$$

Evaluate

$$64$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 3 and 2 to get 5.

$$\left(-2\right)^{5}\left(-2\right)^{0}\left(-2\right)$$

To multiply powers of the same base, add their exponents. Add 5 and 0 to get 5.

$$\left(-2\right)^{5}\left(-2\right)$$

To multiply powers of the same base, add their exponents. Add 5 and 1 to get 6.

$$\left(-2\right)^{6}$$

Calculate -2 to the power of 6 and get 64.

$$64$$

Factor

$$2^{6}$$