Solve (-2)^3+5(-2)^2-k(-2)-5=9

$$( - 2 ) ^ { 3 } + 5 ( - 2 ) ^ { 2 } - k ( - 2 ) - 5 = 9$$

Solve for k

$$k=1$$

Steps for Solving Linear Equation

Calculate -2 to the power of 3 and get -8.

$$-8+5\left(-2\right)^{2}-k\left(-2\right)-5=9$$

Calculate -2 to the power of 2 and get 4.

$$-8+5\times 4-k\left(-2\right)-5=9$$

Multiply 5 and 4 to get 20.

$$-8+20-k\left(-2\right)-5=9$$

Add -8 and 20 to get 12.

$$12-k\left(-2\right)-5=9$$

Add 5 to both sides.

$$12-k\left(-2\right)=9+5$$

Add 9 and 5 to get 14.

$$12-k\left(-2\right)=14$$

Multiply -1 and -2 to get 2.

$$12+2k=14$$

Subtract 12 from both sides.

$$2k=14-12$$

Subtract 12 from 14 to get 2.

$$2k=2$$

Divide both sides by 2.

$$k=\frac{2}{2}$$

Divide 2 by 2 to get 1.

$$k=1$$