Solve (-2)^3+(-3)^2-4^2div(-4)

$$( - 2 ) ^ { 3 } + ( - 3 ) ^ { 2 } - 4 ^ { 2 } \div ( - 4 )$$

Evaluate

$$5$$

Solution Steps

Calculate -2 to the power of 3 and get -8.

$$-8+\left(-3\right)^{2}-\frac{4^{2}}{-4}$$

Calculate -3 to the power of 2 and get 9.

$$-8+9-\frac{4^{2}}{-4}$$

Add -8 and 9 to get 1.

$$1-\frac{4^{2}}{-4}$$

Calculate 4 to the power of 2 and get 16.

$$1-\frac{16}{-4}$$

Divide 16 by -4 to get -4.

$$1-\left(-4\right)$$

The opposite of -4 is 4.

$$1+4$$

Add 1 and 4 to get 5.

$$5$$

Factor

$$5$$