Solve (-2)^3+(-3)^2-(-3)^2-(-2)^5

$$( - 2 ) ^ { 3 } + ( - 3 ) ^ { 2 } - ( - 3 ) ^ { 2 } - ( - 2 ) ^ { 5 }$$

Evaluate

$$24$$

Solution Steps

Calculate -2 to the power of 3 and get -8.

$$-8+\left(-3\right)^{2}-\left(-3\right)^{2}-\left(-2\right)^{5}$$

Calculate -3 to the power of 2 and get 9.

$$-8+9-\left(-3\right)^{2}-\left(-2\right)^{5}$$

Add -8 and 9 to get 1.

$$1-\left(-3\right)^{2}-\left(-2\right)^{5}$$

Calculate -3 to the power of 2 and get 9.

$$1-9-\left(-2\right)^{5}$$

Subtract 9 from 1 to get -8.

$$-8-\left(-2\right)^{5}$$

Calculate -2 to the power of 5 and get -32.

$$-8-\left(-32\right)$$

The opposite of -32 is 32.

$$-8+32$$

Add -8 and 32 to get 24.

$$24$$

Factor

$$2^{3}\times 3$$