Solve (-2)^3+(-3)^2-(-1)^2-(-2)^6

$$( - 2 ) ^ { 3 } + ( - 3 ) ^ { 2 } - ( - 1 ) ^ { 2 } - ( - 2 ) ^ { 6 }$$

Evaluate

$$-64$$

Solution Steps

Calculate -2 to the power of 3 and get -8.

$$-8+\left(-3\right)^{2}-\left(-1\right)^{2}-\left(-2\right)^{6}$$

Calculate -3 to the power of 2 and get 9.

$$-8+9-\left(-1\right)^{2}-\left(-2\right)^{6}$$

Add -8 and 9 to get 1.

$$1-\left(-1\right)^{2}-\left(-2\right)^{6}$$

Calculate -1 to the power of 2 and get 1.

$$1-1-\left(-2\right)^{6}$$

Subtract 1 from 1 to get 0.

$$0-\left(-2\right)^{6}$$

Calculate -2 to the power of 6 and get 64.

$$0-64$$

Subtract 64 from 0 to get -64.

$$-64$$

Factor

$$-64$$