Solve (-2)^3+(+3)^2-(-1)^2-(-2)^5=

$$( - 2 ) ^ { 3 } + ( + 3 ) ^ { 2 } - ( - 1 ) ^ { 2 } - ( - 2 ) ^ { 5 } =$$

Evaluate

$$32$$

Solution Steps

Calculate -2 to the power of 3 and get -8.

$$-8+3^{2}-\left(-1\right)^{2}-\left(-2\right)^{5}$$

Calculate 3 to the power of 2 and get 9.

$$-8+9-\left(-1\right)^{2}-\left(-2\right)^{5}$$

Add -8 and 9 to get 1.

$$1-\left(-1\right)^{2}-\left(-2\right)^{5}$$

Calculate -1 to the power of 2 and get 1.

$$1-1-\left(-2\right)^{5}$$

Subtract 1 from 1 to get 0.

$$0-\left(-2\right)^{5}$$

Calculate -2 to the power of 5 and get -32.

$$0-\left(-32\right)$$

The opposite of -32 is 32.

$$0+32$$

Add 0 and 32 to get 32.

$$32$$

Factor

$$2^{5}$$