Solve (-2)^3+sqrt[3]{-1}-(-4)^3-sqrt{169}=

$$( - 2 ) ^ { 3 } + \sqrt[ 3 ] { - 1 } - ( - 4 ) ^ { 3 } - \sqrt { 169 } =$$

Evaluate

$$42$$

Solution Steps

Calculate -2 to the power of 3 and get -8.

$$-8+\sqrt[3]{-1}-\left(-4\right)^{3}-\sqrt{169}$$

Calculate \sqrt[3]{-1} and get -1.

$$-8-1-\left(-4\right)^{3}-\sqrt{169}$$

Subtract 1 from -8 to get -9.

$$-9-\left(-4\right)^{3}-\sqrt{169}$$

Calculate -4 to the power of 3 and get -64.

$$-9-\left(-64\right)-\sqrt{169}$$

The opposite of -64 is 64.

$$-9+64-\sqrt{169}$$

Add -9 and 64 to get 55.

$$55-\sqrt{169}$$

Calculate the square root of 169 and get 13.

$$55-13$$

Subtract 13 from 55 to get 42.

$$42$$

Factor

$$2\times 3\times 7$$