Solve (-2)^2-4*3*kgeq0

$$( - 2 ) ^ { 2 } - 4 \times 3 \times k \geq 0$$

Solve for k

$$k\leq \frac{1}{3}$$

Solution Steps

Calculate -2 to the power of 2 and get 4.

$$4-4\times 3k\geq 0$$

Multiply 4 and 3 to get 12.

$$4-12k\geq 0$$

Subtract 4 from both sides. Anything subtracted from zero gives its negation.

$$-12k\geq -4$$

Divide both sides by -12. Since -12 is negative, the inequality direction is changed.

$$k\leq \frac{-4}{-12}$$

Reduce the fraction \frac{-4}{-12} to lowest terms by extracting and canceling out -4.

$$k\leq \frac{1}{3}$$